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openRemoteIP - I suspect there's a quick answer.
Posted: Wed Jan 09, 2013 10:01 am
by Lyndon Williams
I used an 1124 temperature sensor on an 8/8/8 interface board locally. Here's a very simple code that worked.....
Code: Select all
from Phidgets.Devices.InterfaceKit import InterfaceKit
localIFK= InterfaceKit()
localIFK.openPhidget()
localIFK.waitForAttach(10000)
sensorvalue = localIFK.getSensorValue(0)
roomtemp = (int)((sensorvalue * 0.22222) - 61.11);
print ("The temperature in this room is: %d" %roomtemp)
Then I put the 1124 on a remote sbc and tried it again.
Code: Select all
from Phidgets.Devices.InterfaceKit import InterfaceKit
remoteIFK= InterfaceKit()
remoteIFK.openRemoteIP("192.168.83.142",5001,"")
remoteIFK.waitForAttach(10000)
sensorvalue = remoteIFK.getSensorValue(0)
roomtemp = (int)((sensorvalue * 0.22222) - 61.11);
print ("The temperature in this room is: %d" %roomtemp)
But Python tells me....
Traceback (most recent call last):
File "C:\Python32\simpleTemperaturSensor.py", line 6, in <module>
remoteIFK.openRemoteIP("192.168.83.142",5001,"")
File "C:\Python32\lib\site-packages\Phidgets\Phidget.py", line 399, in openRemoteIP
result = PhidgetLibrary.getDll().CPhidget_openRemoteIP(self.handle, c_int(serial), c_char_p(IPAddress), c_int(port), c_char_p(password))
TypeError: bytes or integer address expected instead of str instance
I'm sure there is a very simple answer. Can anyone help?
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Wed Jan 09, 2013 2:53 pm
by burley
openRemoteIP has 4 arguments. You have left out serial number.
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Thu Jan 10, 2013 6:11 am
by Lyndon Williams
Hey Brian,
I tried adding the serial number as the third argument. Here is the code....
Code: Select all
from Phidgets.Devices.InterfaceKit import InterfaceKit
remoteIFK= InterfaceKit()
remoteIFK.openRemoteIP("192.168.83.142",5001,45240,"")
# remoteIFK.openRemoteIP(45240,"192.168.83.142",5001,"")
remoteIFK.waitForAttach(10000)
sensorvalue = remoteIFK.getSensorValue(0)
roomtemp = (int)((sensorvalue * 0.22222) - 61.11);
print ("The temperature in this room is: %d" %roomtemp)
I receive the same error. I even put it in as the first argument, which might be inferred from the error message. What am I overlooking here?
The piece in the API document made me believe that serial number could be left out. Here is the excerpt....
openRemoteIP(self, IPAddress, port, serial=-1, password='')
Open this Phidget remotely using an IP Address, securely providing a password,and whether or not to connect to a specific serial number.
Providing a password will open the connection securely depending on if a password is set on the host machine's webservice.
If no serial number is provided, the first available Phidget will be opened. If there are two Phidgets of the same type attached to the system, you should specify a serial number, as there is no guarantee which Phidget will be selected by the call to open().
Parameters:
IPAddress<string>: IP Address or hostname of the Phidget Webservice
port<int>: Port of the Phidget Webservice
serial<int>: The serial number of the device
password<string>: The secure password for the Phidget Webservice
Exceptions:
RuntimeError - If current platform is not supported/phidget c dll cannot be found
PhidgetException: if the Phidget Webservice cannot be contacted
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Thu Jan 10, 2013 9:23 am
by burley
Try running this though obviously replace the IP address with the appropriate one. It is just a simple modification of our default sample code:
Code: Select all
#!/usr/bin/env python
#Basic imports
from ctypes import *
import sys
import random
#Phidget specific imports
from Phidgets.PhidgetException import PhidgetErrorCodes, PhidgetException
from Phidgets.Events.Events import AttachEventArgs, DetachEventArgs, ErrorEventArgs, InputChangeEventArgs, OutputChangeEventArgs, SensorChangeEventArgs
from Phidgets.Devices.InterfaceKit import InterfaceKit
#Create an interfacekit object
try:
interfaceKit = InterfaceKit()
except RuntimeError as e:
print("Runtime Exception: %s" % e.details)
print("Exiting....")
exit(1)
#Event Handler Callback Functions
def inferfaceKitAttached(e):
attached = e.device
print("InterfaceKit %i Attached!" % (attached.getSerialNum()))
def interfaceKitDetached(e):
detached = e.device
print("InterfaceKit %i Detached!" % (detached.getSerialNum()))
def interfaceKitError(e):
try:
source = e.device
print("InterfaceKit %i: Phidget Error %i: %s" % (source.getSerialNum(), e.eCode, e.description))
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
def interfaceKitInputChanged(e):
source = e.device
print("InterfaceKit %i: Input %i: %s" % (source.getSerialNum(), e.index, e.state))
def interfaceKitSensorChanged(e):
source = e.device
print("InterfaceKit %i: Sensor %i: %i" % (source.getSerialNum(), e.index, e.value))
def interfaceKitOutputChanged(e):
source = e.device
print("InterfaceKit %i: Output %i: %s" % (source.getSerialNum(), e.index, e.state))
#Main Program Code
try:
interfaceKit.setOnAttachHandler(inferfaceKitAttached)
interfaceKit.setOnDetachHandler(interfaceKitDetached)
interfaceKit.setOnErrorhandler(interfaceKitError)
interfaceKit.setOnInputChangeHandler(interfaceKitInputChanged)
interfaceKit.setOnOutputChangeHandler(interfaceKitOutputChanged)
interfaceKit.setOnSensorChangeHandler(interfaceKitSensorChanged)
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
print("Exiting....")
exit(1)
print("Opening phidget object....")
try:
interfaceKit.openRemoteIP("192.168.3.197",5001, -1, "")
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
print("Exiting....")
exit(1)
print("Waiting for attach....")
try:
interfaceKit.waitForAttach(10000)
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
try:
interfaceKit.closePhidget()
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
print("Exiting....")
exit(1)
print("Exiting....")
exit(1)
else:
print("Press Enter to quit....")
chr = sys.stdin.read(1)
print("Closing...")
try:
interfaceKit.closePhidget()
except PhidgetException as e:
print("Phidget Exception %i: %s" % (e.code, e.details))
print("Exiting....")
exit(1)
print("Done.")
exit(0)
This works on my machine.
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Thu Jan 10, 2013 9:31 am
by Lyndon Williams
I received the same error. Are you running Python 3.2 or 2.7?
Traceback (most recent call last):
File "C:\Python32\simpleTemperaturSensor.py", line 64, in <module>
interfaceKit.openRemoteIP("192.168.83.142",5001, -1, "")
File "C:\Python32\lib\site-packages\Phidgets\Phidget.py", line 399, in openRemoteIP
result = PhidgetLibrary.getDll().CPhidget_openRemoteIP(self.handle, c_int(serial), c_char_p(IPAddress), c_int(port), c_char_p(password))
TypeError: bytes or integer address expected instead of str instance
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Thu Jan 10, 2013 1:44 pm
by burley
I've got both 2.6 and 3.2.
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Wed Mar 06, 2013 6:32 am
by heritagerobotics
We have tried and tried and tried on any number of machines with the very code that burley provides, and we get the same error every time.....
>>>
Opening phidget object....
Traceback (most recent call last):
File "C:\Python32\SBC-Temp-Test.py", line 64, in <module>
interfaceKit.openRemoteIP("192.168.83.33",5001, -1, "")
File "C:\Python32\lib\site-packages\Phidgets\Phidget.py", line 399, in openRemoteIP
result = PhidgetLibrary.getDll().CPhidget_openRemoteIP(self.handle, c_int(serial), c_char_p(IPAddress), c_int(port), c_char_p(password))
TypeError: bytes or integer address expected instead of str instance
>>>
Is there no one who knows what the problem is or what we can do to fix it?
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Wed Mar 06, 2013 8:24 am
by Lyndon Williams
The error only occurs for me with Python 3.2 or Python 3.3, not with Python 2.7.
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Wed Mar 06, 2013 9:34 am
by burley
Lyndon Williams wrote:The error only occurs for me with Python 3.2 or Python 3.3, not with Python 2.7.
It does appear to be a 3.2 related error.
Re: openRemoteIP - I suspect there's a quick answer.
Posted: Wed Mar 06, 2013 9:46 am
by Lyndon Williams
The same error occurs in Python 3.3 as well. It seems to be something with the ctypes module with Python 3.X, or some out of date coding in C:\Python32\lib\site-packages\Phidgets\Phidget.py.